Question

Suppose now you drop the beaker in the previous question from some height. Will the
range of liquid from orifice B still be more? Justify your answer.
Above picture Is of previous question ​

Answer 1

Answer:

Range =2

(H−h)h

So, R

max

=H

According to question,

R=

2

H

=2

(H−h)h

⇒

4

H

=

(H−h)h

⇒

16

H

2

=(H−h)h

⇒

16

H

2

−Hh+h

2

=0

⇒h=

2

1±

1−4×1×

16

1

H=

2

1±

2

3

H=(

2

1

−

4

3

)H=0.067H

and x+2h=H

⇒x=H−2h=0.866H