Question

suppose P=i–2j–3k and Q=4i–2j+6k then according to P+Q with x axis the angle becomes ???​

Answer 1

Explanation:

P+Q=(i-2j-3k)+(4i-2j+6k.) =5i-4j+3k |P+Q|=√5^2-4^2+3^2. =√25-16+9. =√25-25. =0. angle=P+Q÷|P+Q|. =5i-4j+3k÷0. =0