Math, asked by tanushrimeher2002, 16 days ago

Suppose repetition are not permissible, how many 4 digit numbers can be formed from 1, 2, 3, 5, 7, 8}?

How many numbers contain both 3 & 5?

Answers

Answered by anshulriyanshi

2

Answer:

12 possibilities

Step-by-step explanation:

The possibilities are:-

1235
2357
3578
1253
2135
2153
2375
3257
3275
3587
5378
5387

So, there are 12 possibilities.

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