Math, asked by spidey2765, 1 year ago

Suppose second sister age = x years.
First sister age = ( x+10 ) years.
15 years ago,
1st sister age =x+10-15=(x-5) years.
2nd sister age =(x-15) years.
A.T.Q.
x-5=2(x-15)
=2x-30
X-2x=-30+5
-x=-25
X=25
1st sister age =25+10=35 years.
2nd sister age=25 years.

---------- By Parveen Kumar
----------- Cont no. 8814097348.

Answers

Answered by dhruv8667
1
your answer is right
Answered by Anonymous
2

Step-by-step explanation:

Hia buddy

your answer is absolutely correct

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