Math, asked by rushikeshpatare4, 1 month ago

Suppose Sheetal's birthday is on the Pth of October and Karthik's birthday is on the Qth of November, where P and Q are perfect squares. If Sheetal was born 10 days before Karthik, then the value of P2Q will be.

Answers

Answered by 9334akash
4

Answer:

the answer will be 17

value of p is 25

and for Q is 4

and both are perfect square

and the difference between both birthday is 10 because October has 31 day

Answered by Swarup1998
14

Given data:

Sheetal was born on Pth October and Karthik was born on Qth October

P and Q are perfect squares

Sheetal was born 10 days before Karthik

To find:

Value of P^2 Q

Step-by-step explanation:

Step 1.

The days of October which are perfect squares, are 1, 4, 9, 16 and 25.

October has 31 days in total.

Step 2.

The days of November which are perfect squares are 1, 4, 9, 16 and 25.

November has 30 days in total.

Step 3.

Here the only possible pair to satisfy 'Sheetal was born 10 days before Karthik' is (25th October, 4th November), since 25th October - 4th November = 10 days.

Then P = 25 and Q = 4

Step 4.

Now, P^2 Q

= 25^2 × 4

= 625 × 4

= 2500

Final answer: P^2 Q = 2500

The value of P^2 Q is 2500.

NOTE:

  1. P + Q = 25 + 4 = 29
  2. P - Q = 25 - 4 = 21
  3. P × Q = 25 × 4 = 100
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