Question

Suppose that 10% of all students at Cooley High play a winter sport, that 20% play a spring sport, and that 5% play both a winter and a spring sport. What is the probability that a randomly chosen student plays a winter or a spring sport?

Answer 1

let A=student playing winter game
B=student playing spring game
then P(AUB)=P(A)+P(B)+P(A^B)
=>P(AUB)=10+20-5=25%
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