Suppose that 1l of water is heated for a certain time to rise and its temperature by 2C. If 2l of water is heated for the same time, by how much will its temperature rise?
Answers
The rise in temperature will be 1 °C.
We will use the following equation to get the value of change in temperature of -
Q = m*c*∆t
In this formula, q represents heat energy, m denotes mass, c denotes specific heat capacity and t is for temperature.
Mass can further be represented in terms of volume as -
Density = mass/volume.
Thus, mass = density*volume.
Equation can now be written as-
Q = density*volume*c*∆t
Now, assuming other values same,
Volume1*∆t1 = volume2*∆t2
1*2 = 2*∆t2
∆t2 = 1 °C.
Thus, there will be 1 °C rise in temperature.
Answer:
Heat given to 1 litre water = Q1
Q1 = m1 × s1 × delta t ; Q1 = m × 1 × 2⁰ C
Same amount of heat is given to 2 litres water =Q2
Given Q1 = Q2
m1 × s1 × delta t = m2 × s2 × delta t
m × 1 × 2 = 2m × 1 × delta t => 2 = 2 × delta t
= delta t = 2/2 = 1⁰ C
Rise in temperature for 2 litres of water = 1⁰C