Suppose that a ball is thrown straight up into the air and its height after t second is
2
4 + 48t −16t meters. Determine how long it will take for the ball to reach its maximum
height and determined the maximum height.
Answers
Answer:
1.5 sec
60 m
Step-by-step explanation:
Suppose that a ball is thrown straight up into the air and its height after t second is
2
4 + 48t −16t meters. Determine how long it will take for the ball to reach its maximum
height and determined the maximum height.
Correction
height after t second is = 24 + 48t - 16t²
ball will come back to ground when h = 0
24 + 48t - 16t² = 0
2t² - 6t - 3 = 0
t = (6 ±√(36 +24))/4
=> t = (6 ± 7.75)/4
=> t = 13.75/4 or t = -0.44
=> t = 3.44
t = -0.44 is time represntation if ball has been thrown from ground
then total time taken to come back at ground was = 3.44 - (-0.44)
= 3.88 sec
time for peak including 0.44 time = 3.88/2 = 1.94 sec
Max height would be at = 1.94 - 0.44 = 1.5 sec
Max Height = 24 + 48t - 16t²
= 24 + 48*1.5 -16*(1.5)²
= 24 + 72 - 36
= 60 m