Question

suppose that a box of 10kg is moving towards north with a velocity of 10m/s ,such that it has zero net force of 100N is exerted on it. what is acceleration produced and in which direction​

Answer 1

Answer:

Here friction force against the box motion is f=μmg=0.20×10×10=20N

Here friction force against the box motion is f=μmg=0.20×10×10=20NAs the friction force is greater than the 10 N force, the box will accelerate to left. The velocity or speed will decrease due to the friction.