Question

Suppose that a manufactured product has 4 defects per unit of product inspected. Using
Poisson distribution, calculate the probability of finding a product with 2 defects.
(Given: e "=0.01832)
​

Answer 1

Answer:

1−e

−2

Explanation:

By using Poisson distribution,

P(x;μ)=

x!

e

−μ

μ

x

μ: The mean number of successes that occur in a specified region.

x: The actual number of successes that occur in a specified region.

P(x; μ): The Poisson probability that exactly x successes occur in a Poisson experiment, when the mean number of successes is μ

P(x≥1;μ)=1−P(x=0;μ)

μ=2

x=0 (No defective product)

P(x≥1;2)=1−P(x=0;2)=1−

0!

e

−2

2

0

=1−e

−2

Answer 2

Answer:

I don't know dear I am sorry