Question

Suppose that a steel hoop could be constructed around the earth's equator, just fitting it at a temperature 24°C. What would be the thickness of space between hoop and the earth if the temperature of the hoop were increased by 1.5 °C. αsteel = 1.2 × 10-5 °C-1

with the sum​

Answer 1

Answer:

The increase in hoop length would be

delta L = (2 pi R)*delta T*1.2*10^-5 = 96.2 m

The radius increases by the same factor, 1.2*10^-5*0.2 = 2.4*10^-6.

Multiply that by the original radius.

The new hoop radius is larger by 15.3 m

That is how high the hoop will rise above the surface