Question

Suppose that {aN) is an arithmetic sequence with a1+ a2 + a3 + ..... + a100 = 100 and a101+a102+ ..... + a200= 200. If the value of (a2 - a1) = p, find 1000p.
​

Answer 1

Answer:

d = p(common difference)

s100 = 100

50(2a + 99d) = 100

2a + 99p = 2 - eq 1

s200 - s100 = 200

100(2a + 199d) - (2a + 99p) = 200

100(2a + 199d) - 2 = 200

100(2a + 199p) = 202

2a + 199p = 202/100 - eq 2

subtract eq1 from eq2

100p = 0.02

p = 0.0002

IM 10TH STD BUT I TRIED MY BEST THANKS MAN

Answer 2

Answer:

x + 8x/100 = 769

108x/100 = 769

x = 76900/108

x = 712.03

Hope it will be helpful ✌️