Question

Suppose that at any certain temperature, 20 g of common salt dissolved in 50 g of water makes a saturated solution. Then what is the solubility of common salt in water ? (A) 70 (B) 40 (C) 30 (D) 1000 ​

Answer 1

Explanation:

A saturated ammonium chloride solution will correspond to the actual curve of the graph. At 50∘C , ammonium chloride has a solubility of approximately 50 g per 100 g of water. This means that dissolving 50 g of ammonium chloride in 100 g of water will result in the formation of a saturated solution only at 50∘C .

Answer 2

The solubility of common salt in water is (B)40.

Given:

20 g of common salt dissolved in 50 g of water makes a saturated solution.

To Find:

the solubility of common salt in water

Solution:

To find the solubility of common salt in the water we will follow the following steps:

As we know,

Solubility is equal to molarity for saturated solutions.

Saturated solutions are those in which no more solute can be dissolved.

So,

$Molarity = \frac{mass}{volume \: in \: litres}$

Solubility = $\frac{weight of solute in saturated solution}{weight of solvent in saturated solution}×100 = \frac{20}{50} × 100 = 40$

Henceforth, the solubility of common salt in water is (B)40.

#SPJ2