Question

suppose that four times that square of a number equals 20 times that number.what is the number?

Answer 1

Answer:

$\huge\underbrace\bold\pink{AnswEr}$

$4X^2-20X=0. 4X(X-5)=0. 4X=0. X=0. X-5=0.$

Answer 2

this can be solved by formulating the question according to quadratic equation.

let that number be…say P.

so , according to question,

4(P^2)=20P

=> 4(P^2)-20P=0

=> P(4P-20)=0 —-(taking P common)

=> either P=0 or 4P-20=0

=> either P=0 or P=5