Question

Suppose that in addition to absorption of heat by the sample, the surrounding does 2000kJ of work on the sample, what is ΔU? If a sample gas absorbs 4000kJ of heat.
(6000 kJ)

Answer 1

cwater=4.18Jg∘C




hope this help you.....

Answer 2

Answer:

ΔU = 6000 kJ.

Explanation:

Since we know from the first law of thermodynamics we have,

$\Delta H = \Delta U$ + w.d.................(1)

We know that,

Since $\Delta H = q$......................(2)

So,from (1) and (2) we get,

$q-w.d = \Delta U$..................(3)

Since heat is absorb to the system so,it is positive q = +2000 kJ.

Work is done on the system so ,it is negative = -4000 kJ.

Using equation (3) we get

$\Delta U =$2000 + 4000 = 6000 KJ.