Suppose that P(A)= 3/5 and P(B)=2/3. then
A. P(AUB)≥ 2/3
B.4/15 ≤P(A intersection B) ≤ 3/5
C. 2/5 ≤P(A|B) ≤ 9/10
D. P(A intersection B' ) ≤ 1/3
Answers
Answered by
0
Answer:
Answer
Open in answr app
Open_in_app
Correct option is
D
9
2
P(A
′
∩B
′
)=1−P(A∪B)
=1−[P(A)+P(B)−P(A∩B)]
=1−[
5
3
+
9
4
−
5
3
×
9
4
] [P(A∩B)=P(A)⋅P(B)]
=1−[
45
27+20−12
]=1−
45
35
=
45
10
=
9
2
verified_toppr
Step-by-step explanation:
Answer
Open in answr app
Open_in_app
Correct option is
D
9
2
P(A
′
∩B
′
)=1−P(A∪B)
=1−[P(A)+P(B)−P(A∩B)]
=1−[
5
3
+
9
4
−
5
3
×
9
4
] [P(A∩B)=P(A)⋅P(B)]
=1−[
45
27+20−12
]=1−
45
35
=
45
10
=
9
2
verified_toppr
Similar questions