Suppose that P (A/B) = 0.7, P(A) = 0.5 and P(B) = 0.2 then P(B/A) is
Answers
Answer:
we know that P(B/A)=P(A/B)P(B)/P(A)
=(0.7)(0.2)/0.5
=0.14/0.5=0.28
The value of P(B/A) is 0.28.
Given: P(A/B) = 0.7, P(A) = 0.5 and P(B) = 0.2
To Find: The value of P(B/A).
Solution:
- We know that the formula of P(A/B) can be given by the formula,
P(A/B) = P (A ∩ B) / P (B) ...(1)
and P(B/A) = P (A ∩ B) / P (A) ...(2)
Coming to the numerical, we have;
P(A/B) = 0.7, P(A) = 0.5 and P(B) = 0.2. So we need to find the value of P(A∩B). Putting respective values in (1), we get;
P(A/B) = P (A ∩ B) / P (B)
⇒ 0.7 = P (A ∩ B) / 0.2
⇒ P (A ∩ B) = 0.7 × 0.2
⇒ P (A ∩ B) = 0.14
Now, from (2), we have;
P(B/A) = P (A ∩ B) / P (A)
Putting respective values, we get,
⇒ P(B/A) = 0.14 / 0.5
⇒ P(B/A) = 0.28
Hence, the value of P(B/A) is 0.28.
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