Suppose that p q and rs are two chords of a circle intersecting at a point o. It is given that p o = 3 cm and so = 4 cm. Moreover, the area of the triangle p or is 7 cm2 . Find the area of the triangle qos.
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It is given that,
PQ ,RS are two chords of a circles intersecting at a point O.
PO = 3cm , SO = 4cm
Area of ∆POR = 7cm²
Proof:
Inscribed - angle theorem:
In ∆POR, ∆SQO,
<PRO = <SQO
/* Inscribed angles over PS*/
<RPO = <QSO
/* Inscribed angles over CD*/
<POR = <SOQ
∆POR ~ ∆SQO
/* The areas of two similar triangles are in the ratio of the squares of the two corresponding sides */
∆QOS/∆POR = (OS)²/(OP)²
=> ∆QOS/7 = 4²/3²
=> ∆QOS = (7×16)/9
=> area of ∆QOS = 112/9 cm²
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