Question

Suppose that samples of size n=4 are used to construct the sampling distribution of the sample mean. What is the largest element of the sampling distribution of the sample mean? Round off your answer (in kg) to the nearest hundredths. Do not include units.

Answer 1

Answer:

suppose that samples of size

Answer 2

Disclaimer

The question is incomplete and hence the complete question is mentioned here

The answer for this question is shown below !!!

Concept

The mean, or average of the supplied numbers, is computed by dividing the total number of numbers by the sum of the given numbers.

Given

The data chart is given and the sample of size n = 4

Find

We need to find that Sample mean and the largest element of the sampling distribution of sampling mean  

Solution

We know that The mean, or average of the supplied numbers, is computed by dividing the total number of numbers by the sum of the given numbers.

Therefore

Mean  = $\frac{sum of the observation}{total number of observations}$

Mean = $\frac{48+56+55+53}{4}$

Mean = 53kg

Here the Sampling mean is 53kg

The largest element of the sampling distribution of the sample mean is 64 kg

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