Suppose that the division x divided by 5 leaves a remainder 4 and the division x divided by 2 leaves a remainder 1. Find the ones digit of x
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Divided by remainder
5. (-1) 4
2 (-1) 1
L.C.M. of 5 and 2=10
Hence,x=10-(difference between divisor and remainder)
=10-1
=9
Therefore,smallest value of 'x'=9
Therefore,digit at unit place of 'x'=9
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