Suppose that the function 'f' is differentiable at x=3 and lim h->0.. f(h) /h =1 , lim h->0 f(3+h) = 5. Find f(3) and f'(3). Such that F has property : f(x+y) = f(x) + f(y) + 3xy, for all values of x and y.
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Answer:
As f(x) is differentiable at x=1
5=
h→0
lim
h
f(1+h)
assuming 0/0 form
Using L-hospital's rule,
5=
h→0
lim
1
f
′
(1)
∴ f
′
(1)=5
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