Question

Suppose that the length of life (in hours) of a semiconductor variable following a Weibull distribution with parameters a = 0.025 and B= 0.5. What is the probability that such a semiconductor will be in operation even after 4000 hours? ​

Answer 1

4000/30000
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Answer 2

Answer:

Question:

Suppose that the service life (in hours) of a semiconductor device is a random variable having the Weibull distribution with α=0.025α=0.025 and β=0.500.β=0.500.

What is the probability that such a device will still be in operating condition after 4,000 hours?

Weibull distribution:

The Weibull function is a two-parameter continuous probability distribution where the parameters are alpha and beta. The probability in the case of Weibull distribution can be calculated as:

p(X≤x)=1−e−(x/α)βp(X≤x)=1−e−(x/α)β

We can also use the excel function =WEIBULL(x,α,β,Cumulative)=WEIBULL(x,α,β,Cumulative) to find the probability of x with parameter alpha and beta.

Answer and Explanation:

It is given in the question that the service life of a semiconductor device has Weibull distribution with parameters given as {eq}\alpha =...

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