Suppose that the radius of the earth becomes twice of its original radius without any change in its mass. Then what will be your weight?
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suppose that your mass is m. Let the gravitational force of earth is g1.
now,
g1=GM/R^2.....(1) (G= gravitational constant, M=mass of earth, R=original radius of earth)
if the radius be twice of its original,
then the radius=2R
g2=GM/4R^2
=g1 ÷4. (from (1). ).......(2)
firstly, your weight was w1=mg1
secondly, your weight is=mg2
=mg1÷4 ( from (2). )
so, your weight will be one fourth of original.
now,
g1=GM/R^2.....(1) (G= gravitational constant, M=mass of earth, R=original radius of earth)
if the radius be twice of its original,
then the radius=2R
g2=GM/4R^2
=g1 ÷4. (from (1). ).......(2)
firstly, your weight was w1=mg1
secondly, your weight is=mg2
=mg1÷4 ( from (2). )
so, your weight will be one fourth of original.
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