Question

suppose that the rafius r and area A =πr^2 of a circle differentiable function of t. Write an equation that relates dA/dt to dr/dt​

Answer 1

$da \div dt = 2\pi \: r \: dr \div dt$

Answer 2

Answer:

d A / dt = 4 π r [ d r / dt ]

Step-by-step explanation:

Since:

Area of circle = A(t) = Area is the function of time "t"

Radius of circle = r(t) = radius is the function of time "t"

W Know that

According to the formula of area of circle

                   A(t) = 2 π r²(t).                    ...(1)

Taking derivative of equation (1) with respect to time "t" on both sides

         d A(t) / dt = d (2 π r²(t)) / dt

because " 2 π " is constant here so

⇒        d A(t) / dt = 2 π [ d ( r²(t) ) / dt ]    

Using power rule of derivatives                  

          d A(t) / dt = 2 π ×2 r [ d ( r(t) ) / dt ]

          d A(t) / dt = 4 π r [ d ( r(t) ) / dt ]               ....(2)

Equations (2)  is the required equation