Question

Suppose that Wing Commander abhinandan are 80 kg. If F-16 drops the support of M-21 and jumps to a height of 1000 m. If they fall freely to the height of half the height, then after getting slowed due to the parachute, they reach the final velocity of 10 m / s on the ground, then the work done by the resistance force will be:​

Answer 1

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Answer 2

Answer: The resistance force will be 8 N.

Explanation:

Given that,

Mass m = 80 kg

Height h = 1000 m

Final velocity v = 10 m/s

We know that,

Potential energy = kinetic energy

$mgh=\dfrac{1}{2}mv^{2}$

$10\times 500\times 2= v^2$

$v = 100 m/s$

Using equation of motion

$v^2=u^2+2as$

$2as= 10^2-100^2$

$a = -9.9\ m/s^2$

The resistance force is

$F_{\mu}= mg+ma$

$F = 80(10-9.9)$

$F = 8 N$

Hence, The resistance force will be 8 N.