Suppose that Wing Commander abhinandan are 80 kg. If F-16 drops the support of M-21 and jumps to a height of 1000 m. If they fall freely to the height of half the height, then after getting slowed due to the parachute, they reach the final velocity of 10 m / s on the ground, then the work done by the resistance force will be:
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Potential energy = mgh
where
m = mass
g = acceleration due to gravity = 9.8 m/s^2
h = height.
Wing commander potential energy at height 1000m =
80*g*1000 = 80000g = 784000
All this energy should be converted to kinetic energy when he come to ground.
Final velocity on ground = 10 m/s
Kinetic Energy = mv²/2
KE = 80*10*10/2 = 4000.
The difference in PE and KE = PE – KE = 784000 – 4000 = 78000.
Hence work done is 78000 Joule by the parachute resistance force.
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if equation of motion we get.8N therefore 8N= 50.98 Kj..not true answer
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