Question

Suppose that your body has uniform density equal to 0.95
times that of water. If you float in a swimming pool, what
fraction of your bodys volume is above the water surface?​

Answer 1

Answer:

Answer is 0.05 at it is solved by my teacher

Answer 2

Answer:

$5%$% of the body is above the water surface.

Step-by-step explanation:

Given: your body has a uniform density equal to 0.95 times that of water

To find: what fraction of your body's volume is above the water surface?​

Solution:

Let $V_{body}$ to be the total volume of the body.

Let $V$ be the submerged volume of the body.

Then

$P_{body} /P_{water}=0.95$

Since the body is floating, $W=F_{b}$

$P_{body}$ × $V_{body}$ × $g$ $=P_{water}$ × $V$ × $g$

Solving.

$P_{body} /P_{water} =V/V_{body} =0.95$

Calculate $V$.

$V=0.95 V_{body}$ → $95$% of the body is submerged.

Therefore, $5$% of your body's volume is above the water surface.