Math, asked by sheensvt, 11 months ago

Suppose the area of the rectangle is 144.4 m² and the length is 14 m longer than the width. Find the length and width of the rectangle?

Answers

Answered by Acharya01
7

Answer:

Area = 144.4m^2

bredth= "x" (assume)

Length(l) = (14+x) m

Area = (Length)(breadth)

or, (14+x)(x) = 144.4m^2

or, x^2 + 14x = 144.4

or, x^2+14x - 144.4 = 0

since the quadratic equation has no real roots . length and breadth cannot be solved.

Answered by syed2020ashaels
0

Answer:

The answer to the given question is the quadratic equation has no real roots. Therefore, the length and width of the rectangle cannot be solved.

Step-by-step explanation:

Given :

The area of the rectangle is 144.4 m²

length of the rectangle is 14 m longer than the width.

To find :

length and width of the rectangle.

Solution :

let the width of the rectangle be x m

Therefore, the length will be( 14+x )m.

The formula to find the area of the rectangle is the product of the length and the width.

(14 + x).x = 144.4

on multiplying the left side, we get the values as

14x +  {x}^{2}  = 144.4

The value on the right side subtracts the value on the left side

 {x}^{2}  + 14 x - 144.4 = 0

The zeroes for the given expression do not exist.

This quadratic equation has no real roots.

Hence the length and width of the rectangle cannot be solved.

# spj3

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