Question

suppose the displacement of a particle is related to a time according to expression S=ct3.What are the dimensions of the constant c?​

Answer 1

Answer:

According to dimensional analysis.

the dimension of LHS and RHS should be same.

S = L

so, ct³ =[ L]

⇒c T³= L

⇒c =[L T^(-3)]

where L is for length, T for time and M for mass

Answer 2

Explanation:

S = ct³

[ M°L1T°] = [M^aL^bT^c] [M°L°T³]

=> [ M°L1T^(-3)] = [ M^aL^bT^c]

comparing

a = 0, b = 1 ,c = -3

=> dimension of c = [ M°L^1T^-2]

Hope this helps you