Question

Suppose the displacement of two light waves are y1 = 6 m and y2 = 3 m respectively. What will be the resultant displacement due to superposition? Consider a sodium light source emit two waves having path difference is 3600 Å. What will be happened if the source is coherent?

Answer 1

Answer:

Given that,

y¹=4 sin wt

y²=3 cos wt

Amplitude of frist and second wave is 4cm and 3cm.so amplitude of resultant wave is

y¹=.√(4)²+(3)²

= 5cm

Answer 2

Answer:

3$\sqrt{5}$

Explanation:

Given that,

y1  =6

y2 =  3

Amplitude of first and second wave is 6m and 3m. So, the amplitude of resultant wave is

y = $\sqrt{6^{2} +3^{2} }$

  = 3$\sqrt{5}$