Question

Suppose the earth increases it speed of rotation. At what new time period will the weight of a body on the equator becomes zero ? (Take, g = 10 ms^(-2) and radius of earth R = 6400 km)

Answer 1

The weight will become zero, when

g'=0 or g−Rω2=0 (on the equater g'=g−Rω2)

or ω=gR−−√

∴2πT=gR−−√orT=2πgR−−√

Substitution the values, T=2π6400×10310−−−−−−√3600h

or T=1.4h

Thus, the new time period should e 1.4h instead of 24h for the weight of a dody to de zero on the equater .

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Answer 2

Answer:

1.4h instead of 24 h