suppose the earth shrinks such that its radius decreases of half the present value what will be the acceleration due to gravity on the surface
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Answered by
78
since we know g=GM/R²
so if the radius decrease by half then new value of g will be equal to GM/(R/2)²
4GM/R²
which means that the acceleration due to gravity will increase by 4 times
so if the radius decrease by half then new value of g will be equal to GM/(R/2)²
4GM/R²
which means that the acceleration due to gravity will increase by 4 times
Answered by
52
g=GM/(R/2)^2
g=4GM/R^2
g=4g(g=GM/R^2)
g=4×9.8
g=39.2 so it increases 4 times
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