Suppose the energy of an electron is hydrogen – like atom is given asEn=- 54.4/neV where n e N. Calculate the following : a) Sketch the energy levels for this atom and compute its atomic number. b) If the atom is in ground state, compute its first excitation potential andalso its ionization potential.
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Answer:
Maximum energy is liberated for transition E
n
→1 and minimum energy for E
n
→E
n−1
Hence,
n
2
E
1
−E
1
=52.224eV...(i)
and
n
2
E
1
−
(n−1)
2
E
1
=1.224eV...(ii)
Solving Eqs. (i) and (ii) we get
E
1
=−54.4eV;
and n=5
But E
1
=−
1
2
13.6Z
2
⇒Z=2
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