Question

Suppose the exact charge neutrality does not hold in a
world and the electron has a charge 1% less in magnitude
than the proton. Calculate the Coulomb force acting
between two blocks of iron each of mass 1 kg separated
by a distance of 1 m. Number of protons in an iron atom
= 26 and 58 kg of iron contains 6 x 10 % atoms.
Solution : Each atom of iron will have a net positive charge

Answer 1

Answer:

F = 1.66∗10^21 N      

Explanation:

Electric force between two charged object are:

F= kQ1Q2/r2

Where k = 1/4piEo

Now, we need to find out the charge of the iron samples:

Each bar has a mass of 1 kg.

So, the number of atoms in each bar is:

Na = m/n

=6∗10^26/58

=1.0344∗10^25atoms

Each atom has 26 protons:

Np = 26Na

= 2.69∗10^26 protons

The exceeding charge of the each rod is:

Q = 0.01Na∗qe

=4.304∗10^5C

Finally, the force between two rods:

F=kQ1Q2/r2

= 9∗10^9 x (4.304)^2 x 10^10/ 1^2

= 1.66∗10^21 N