Question

Suppose the exact charge neutrality does not hold in a
world and the electron has a charge 1% less in magnitude
than the proton. Calculate the Coulomb force acting
between two blocks of iron each of mass 1 kg separated
by a distance of 1 m. Number of protons in an iron atom
= 26 and 58 kg of iron contains 6 x 10 atoms.
26​

Answer 1

Answer:

To calculate :

The coulomb force acting between blocks of iron.

Solution :-

Each atom of iron will have a net Postive charge 26×0.01×1.6×10^(-19) C on it in the assumed world. The total positive charge on 1 kg block would be

$\frac{6 \times {10}^{28} }{58} \times 26 \times 1.6 \times {10}^{ - 21}$

and, that is equal to

=

$4.3 \times {10}^{5} coulomb$

The coluomb force between the two blocks is

=

$\frac{1}{4\pi \: e} \times \: \frac{q1q2}{ {r}^{2} }$

=

$9.0 \times {10}^{9} \times ( {4.3 \times {10}^{5} })^{2}$

and that is equal to ;

$1.7 \times {10}^{21} \: newton$

This is the required answer!!

Answer 2

Answer:

7m is the best place for the kids