Question

Suppose the masses of the calorimeter, the water in it and the hot object made up of copper which is put in the calorimeter are the same. The initial temperature of the calorimeter and water is 30 °C and that of the hot object is 60 °C. The specific heats of copper and water are 0.09 cal / (gm °C) and I cal / (gm "C) respectively. What will be the final temperature of water? Given za T20 T 60CT=?​

Answer 1

Answer:

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Explanation:

Heat gain by water and calorimeter = heat gain by hot object. let m (in gram ) be mass of each i.e., water, calorimeter and hot object. calorimeter and hot object both are made up of copper