Suppose the medians AA' and BB' of triangleABC intersect at right angles. If BC is 3 and AC is 4 find length of side of AB
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answer is 5
Step-by-step explanation:
ab is the hypotenuse
AC is perpendicular
bc is the hypotenuse....therefore hypotenuse square = base square +perpendicular square
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Answer:
AB = 4 units
Step-by-step explanation:
This problem can be solve using Pythagoras Theorem.
This theorem is used for Right angle triangle. In right angle triangle if one of the side is unknown then we can find it by using formula:
(Hypotenuse)² = (Base)² + (Perpendicular)²
Firstly take the ΔABC, We have
BC = 3, AC = 4 and AB = ?
⇒ (AB)² = (AC)² + (BC)²
⇒ (AB)² = 16 + 9
⇒ (AB)² = 25
⇒ AB = 5
The length of side of AB = 5 unit.
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