Question

Suppose the object in figure shown is the brass plate of an outdoor sculpture. It experiences shear
forces as a result of an earthquake. The frame is 0.80 m and 0.50 cm thick. Calculate the shear
strain produced in this object if the displacement x is 0.16 mm. (Shear modulus = 3.5 * 1010 Pa)
Х
KN
F
h​

Answer 1

Given:

The frame of the brass plate is 0.80 m and 0.50 cm thick.

x = 0.16 mm

Shear modulus = 3.5 * 1010 Pa

To find:

The shear strain =?

Explanation:

The brass plate experiences shear forces as a result of an earthquake.

So the shear will be produced on the length of the brass plate. not on breadth.

So h = l = 0.80 m

Shear strain = $\displaystyle \frac{x}{h}$

                     =   $\displaystyle \frac{0.16 \times 10^{-3}}{0.80}$

S = 2 $\displaysyle \mathbf {\times \ 10^{-4}}$

Refer to the following fig: