Suppose the probability for A to win a game against B is 0.4. If A has an option of playing either a beet of 3 games" or a "best of five game" match against B, which option should A choose so that the probability of his winning is higher?(No game ends in draw)
NOTE: SOLVE THE SUM WITHOUTG USING ANY FORMULA AND GIVE ALL DETAILS.
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Step-by-step explanation:
to probability of a to win is 0.4
for a beet of 3 games the probability is (0.4)^3=0.064
for best of 5 the probability is (0.4)^5
so the probability is higher in best of 5 so he would choose it
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