Suppose the spheres A and B in Exercise 1.12 have identical sizes. A third sphere of the same size but uncharged is brought in contact with the first, then brought in contact with the second, and finally removed from both. What is the new force of repulsion between A and B?
Answers
Answer:
The force of attraction between the two sphere is
Explanation:
Distance between the spheres,
Initially, the charge on each sphere,
When sphere A is touched with an uncharged sphere C, amount of charge from A will transfer to sphere C. Hence, charge on each of the sphere, A and C,
When sphere C with charge
is brought in contact with sphere B with charge q, total charges on the system will divide into two equal halves given as,
Each sphere will share each half. Hence, charge on each of the spheres, C and B, is
Force of repulsion between sphere A having charge
and sphere B having charge
Therefore, the force of attraction between the two sphere is
Explanation:
Distance between the spheres, A and B, r = 0.5m
Initially, the charge on each sphere,
When sphere A is touched with an uncharged sphere C, amount of charge from A will transfer to C. Hence, charge on each of the spheres, A and C is
When sphere C with charge is brought in contact with sphere B with charge q, total charges in the system will divide into two equal halves given as,
Each sphere will share each half. Hence charge on each of the spheres, C and B is
=
=
=
Hence, the force of attraction between the two spheres is