Question

Suppose the tube in the previous problem is kept vertical with A upward but the other conditions remain the same.

Answer 1

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Answer 2

$<b>Now, (a). We know volume rate of the flow does not depends upon the the height of the pipe, since pipe.</b>$

∴ Velocity of the fluid will remains unchanged.

∴ (a). At A,

$<b>Area × Velocity = 1 cm³/s.</b>$

4/100 cm² × Velocity = 1

∴ Velocity = 25 cm/seconds.

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(b). At B,  

Area × Velocity = 1 cm³/s.

2/100 × Velocity = 1

$<b>Velocity = 50 cm/seconds.</b>$

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(c). Pressure difference, will be affected, this is because, there will be the gravitational work also which will be included.

$<b>Using the Bernoulli's equation,</b>$

      Using the Bernoulli's Equation,

P₁ + h₁ρg + 1/2 ρv₁² = P₂ + h₂ρg + 1/2 ρv₂²

∴ P₁ - P₂ = 1/2 ρ(v₂² - v₁²) + ρg(h₂ - h₁)

∴ P₁ - P₂ = 1/2 × 1 × (50² - 25²) + 1 × 1000(15/16)

∴ P₁ - P₂ = 937.5 + 937.5

∴ P₁ - P₂ = 1875 dyne/cm² or 187.5 Pa.

$<b>Hence, the pressure difference is 187.5 Pa.</b>$  

Hope it helps.