Suppose the two photographs had been taken at an interval of 10 sec if a distance of 100m is shown by 1cm in these photographs ,calculate the speed of the faster car.
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Answer: Given, Speed for first 15 minute = 40km/h
Speed for next 15 minute = 60 km/h
We know that,
Distance = Speed X Time
Therefore, Distance covered in first 15 minute i.e. 0.25 hour = 40 km/h X 0.24 hour = 10 km
Distance covered in next 15 minute = 60 km/h X 0.25 hour = 15 km
15 minute = ¼ hour = 0.25 hour
Thus, total distance covered = 10 km + 15 km = 25 km
Hence, Answer (ii) is correct
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