Question

Suppose the velocity of the particle is given by the: v = 10 + 2 t2 where v is in m/s and t is in sec .Find the instantaneous acceleration when t = 2 sec ?

Answer 1

Answer:

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Answer 2

Answer:

The instantaneous acceleration is $8m/s^{2}$.

Explanation:

It is given that $v=10+t^{2}$

Differentiating w.r.t time.

$\frac{dv}{dt} =\frac{d}{dt}(10+2t^{2} )$

$a =\frac{d}{dt}(10)+\frac{d(2t^{2} )}{dt}$

It is because acceleration is rate of change of velocity.

$a=0+4t$

$a=4t$

At time $t=2sec$

$a=4(2)$

$a=8m/s^{2}$

Hence, instantaneous acceleration is $8m/s^{2}$

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