Question

Suppose there are 2 types of animals i.e, peacock and deer. There heads and legs are 80 and 200 respectively when we count,then how many no. of peacock and deer are there in the zoo ??

Answer 1

Hope it helps!!!!

Let x and y be the number of deer and peacocks in the zoo respectively.

Then,

x + y = 80 ...(i)
and
4x + 2y = 200 or 2x + y = 100 ...(ii)

Solving (i) and (ii),

We get,

x = 20, y = 60.

#Be Brainly✌️

Answer 2

Hope it helps u dear.