Question

Suppose there are five teams in some sport participating in some tournament. Each team contains 8 players. We would like to choose one of the players of one of the teams to lead an opening ceremony. How many ways do we have to do it?

Answer 1

Answer:

I feel that the answer is 40.

Please tell me if this is the correct answer

Answer 2

Answer:

We can do it in 40 different ways

Step-by-step explanation:

Number of teams = 5

Number of players in a team = 8

Total number of players in the tournament = $5 \times 8 = 40$

We have to choose any one of the 40 players to lead the opening ceremony. So, the available number of combinations are given by,

x = ${}_^{40}C_{1}$ = 40

Thus, our answer is 40.

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