Question

Suppose there are two circuits... circuit A and circuit B....In circuit A there a 6 V battery and a copper wire connecting positive terminal of battery to negative terminal (no resistor in circuit A and no other component)...In circuit B there is also a 6V battery a copper wire and a bulb.....Now my question is that in which circuit more electrical energy is used??? explain the reason..!

Answer 1

in circuit B is there will be more electrical energy used, as tungsten is mostly used in electrical bulbs and tungsten is a resistor that's why electricity have to done some work against it so in circuit B there will be more electrical energy is used