Suppose there are two form of a specific gene in population the frequency of dominant allele is 0.6 and that of a recessive allele is 0.4 it later date it was found that the frequency of dominant allele 0.8 and that of the recessive allele is 0.2 this change in allele frequency tells that certainly there is
Answers
Explanation:
According to the Hardy-Weinberg law, the allele frequencies in a population remain constant under absence of factors responsible for evolution (natural selection, migration, genetic drift). It states that the sum of all genotype frequencies can be represented as the binomial expansion of the square of the sum of p and q. This sum is equal to one. (p + q)2 = p
2
+ 2pq + q
2
= 1. Here p is the frequency of the "A" allele and q is the frequency of the "a" allele in the population. Thus, p
2
represents the frequency of the homozygous genotype AA, q
2
is the frequency of the homozygous genotype aa, and 2pq represents the frequency of the heterozygous genotype Aa. Further, it also states that the sum of the allele frequencies for all the alleles at the locus should be 1, so p + q = 1. In the question, the frequency of recessive allele is (a) = (0.4) and frequency of dominant allele is (A) = (0.6). Since (p + q)2 = p
2
+ 2pq + q
2
= 1; hence, frequency of heterozygotes= (2pq = 2 x 0.6 x 0.4 = 0.48). Frequency of homozygous genotype aa = (q
2
= 0.16). Frequency of homozygous dominant AA = (p
2
= 0.36). So, the correct option is D.
0.36........
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