suppose three number are in the ratio 4 : 5 : 6: .if the sum of the samallest and the largest number is equal to the sum of the third number and 55, find the three number
jha0001:
let third no. be x 4x + 6x = 5x + 55 10x - 5x = 55 ==> 55/5 = x ===> 11 1st no. --- 4 x 11 = 44 2nd no. --- 5 x 11 = 55 3rd no. ---- 6 x 11 = 66
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Let the three numbers be 4x, 5x and 6x respectively.
Given : The sum of the samallest and the largest number is equal to the sum of the third number and 55
According to the question,
=> 4x + 6x = 5x + 55
=> 10x - 5x = 55
=> 5x = 55
=> x = 55/5 = 11
Therefore,
First number = 4x = 4 × 11 = 44
Second number = 5x = 5 × 11 = 55
Third number = 6x = 6 × 11 = 66
Hence,
The three numbers are 44, 55 and 66 respectively.
Let the three numbers be 4x, 5x and 6x respectively.
Given : The sum of the samallest and the largest number is equal to the sum of the third number and 55
According to the question,
=> 4x + 6x = 5x + 55
=> 10x - 5x = 55
=> 5x = 55
=> x = 55/5 = 11
Therefore,
First number = 4x = 4 × 11 = 44
Second number = 5x = 5 × 11 = 55
Third number = 6x = 6 × 11 = 66
Hence,
The three numbers are 44, 55 and 66 respectively.
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