Question

Suppose two bodies A and B having equal masses are kept at heights of h and 3h respectively the ratio of their potential energies will be

Answer 1

Answer:

1:3

Explanation:

potential energy is mgh

so PE directly proportional to h

since one is h and other is 3h

so ratio comes out to be 1:3

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Answer 2

Ratio of potential energy will be 1:3

Explanation:

We have given two bodies of equal mass

So $m_1=m_2$

Height of first object is $h_1=h$

And height of second object $h_2=3h$

Acceleration due to gravity $=gm/sec^2$

We know that potential energy is given by $P_1=mgh_1=mgh$

Potential energy of second object $P_2=mgh_2=mg3h=3mgh$

So ratio of potential energy will be $\frac{P_1}{P_2}=\frac{mgh}{3mgh}=\frac{1}{3}$

So ratio of potential energy will be 1:3

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