Question

suppose u have given a circle.draw a construction.

Answer 1

★ Steps of construction :-

(a) Take any three points A, B and C on the circle.

(b) Join AB and BC.

(c) Draw perpendicular say LM of AB.

(d) Draw perpendicular PQ of BC.

(e) Let LM and PQ intersect at point O.

Then O is the centre of the circle.

★ Verification :-

O lies on the perpendicular of AB.

OA = OB ……….(i)

O lies on the perpendicular of BC.

OB = OC ……….(ii)

From eq. (i) and (ii), we observe that

OA = OB = OC = (say)

Three non-collinear points A, B and C are at equal distance (r) from the point O inside the circle.

Hence, O is the centre of the circle.

Answer 2

Answer:

Question ⤵

Suppose you have given a circle. Draw a construction .

Answer ⬇

★ Steps of construction :-

(a) Take any three points A, B and C on the circle.

(b) Join AB and BC.

(c) Draw perpendicular say LM of AB.

(d) Draw perpendicular PQ of BC.

(e) Let LM and PQ intersect at point O.

Then O is the centre of the circle.

★ Verification :-

O lies on the perpendicular of AB.

OA = OB ……….(i)

O lies on the perpendicular of BC.

OB = OC ……….(ii)

From eq. (i) and (ii), we observe that

OA = OB = OC = (say)

Three non-collinear points A, B and C are at equal distance (r) from the point O inside the circle.

Hence, O is the centre of the circle.

Thanks..